Computers and Technology
Computers and Technology, 22.08.2019 02:30, pino40

Computers in a peer to peer network belong to a

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Computers and Technology, 22.06.2019 01:50, divine134
A.) generate scaffolding to create database for your application. develop all the entities identified in assignment #2. add any additional that may be identified later. b.) add data validation rules to the models that are appropriate for your application and data. c.) create links for each scaffold in the header section. part 2: application updates [30 points] a.) add two additional views to the "home" controller you created in assignment #1. b.) the two views should be named as “privacy" and "". c.) link the two newly created views in the footer section. hint: you would need to modify the “home" controller definition and create “privacy. html. erb" and “.html. erb" files in appropriate locations.
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Computers and Technology, 22.06.2019 11:30, mmimay3501
What do character formats do for your document's message? a. set the tone b. provide organization c. provide clarity d. set how texts align with documents
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Computers and Technology, 23.06.2019 17:00, kyleemarie2003
Companies that implement and apply an information system effectively can create
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Computers and Technology, 23.06.2019 17:30, Annlee23
When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?
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