What does a knowledge management system do

Define a class named movie. include private fields for the title, year, and name of the director. include three public functions withprototypes void movie: : settitle(cstring); , voidmovie: : setyear(int); , void movie: : setdirector(string); . includeanother function that displays all the information about a movie. write a main() function that declares a movie object namedmyfavoritemovie. set and display the object's fields. this is what i have but know its wrong since it will notcompile: #include#includeusing namespace std; //class declarationclass movie{private: string movietitle ; string movieyear; string directorname; public: void settitle(string title); void setyear(string year); void setdirector(string director); void displayinfo(); }; //class implementationvoid movie: : settitle(string title){ movietitle = title; cout< < "what is the title of themovie? "< > temp; myfavoritemovie. settitle(temp); cout< < "enter movie year"< > temp; myfavoritemovie. setyear(temp); cout< < "enter director'sname"< > temp; myfavoritemovie. setdirector(temp); //display all the data myfavoritemovie. displayinfo(); system("pause"); return 0; this code is not entirely mine someone on cramster edited my firstcode but then i try manipulating the new code and i still get acompile error message : \documents\visual studio 2008\projects\movie\movie\movie. cpp(46) : error c2679: binary '< < ' : no operator found which takes aright-hand operand of type 'std: : string' (or there is no acceptableconversion)c: \program files (x86)\microsoft visual studio9.0\vc\include\ostream(653): could be'std: : basic_ostream< _elem,_traits> & std: : operator< < > (std: : basic_ostream< _elem,_traits> & ,const char *)w

Q14 what is most important for you to choose before you build a network? a. private network b. nos c. network media d. network protocol e. directory service

The initial tableau of a linear programming problem is given. use the simplex method to solve it. x 1 x 2 x 3 s 1 s 2 z 1 2 4 1 0 0 8 3 4 1 0 1 0 10 minus3 minus12 1 0 0 1 0 the maximum is nothing when x 1equals nothing, x 2equals nothing, x 3equals nothing, s 1equals3, and s 2equals0. (be sure to simplify to lowest terms if necessary.)