What is the limiting reactant if 4.0 g of nh3 react with 8.0 g of oxygen?

              Oxygen is the Limiting Reagent

The Balance Chemical Equation is as follow,

                             4 NH₃  +  5 O₂     →      4 NO  +  6 H₂O

Finding the Limiting Reagent;

According to Balance equation,

               68.12 g (4 mol) NH₃ reacts with  =  160 g (5 mol) of O₂

So,

                      4.0 g of NH₃ will react with  =  X g of O₂

Solving for X,

                       X  =  (4.0 g × 160 g) ÷ 68.12 g

                       X  =  9.40 g of O₂

It means 4.0 g of NH₃ requires 9.40 g of O₂, while we are provided with 8.0 g of O₂ which is limited. Therefore, O₂ is the limiting reagent and will control the yield of products.

the answer is definitely c.

the answer is 1 i believe