How many molecules of dinitrogen pentoxide are in 1.39 moles of dinitrogen pentoxide

Explanation:

According to Avogadro's number, it is known that there are atoms present in 1 mole of a substance.

Therefore, molecules or atoms present in 1.39 moles will be as follows.

             No. of atoms = no. of moles × Avogadro's number

                                    =

                                    = atoms

Thus, we can conclude that there are atoms of dinitrogen pentoxide in 1.39 moles.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles