Determine the volume occupied by 0.582 mol of a gas at 15 degrees celsius if the pressure is 81.8 kpa?

Ideal gas law:
PV=nRT    ⇒V=(nRT)/P
P=pressure
V=volume
n=number of moles
R=gas constant= 0.082 atm.litres/ºK mol
T=temperature

P=81.8 Kpa * (1 atm / 101.325 Kpa)≈0.81 atm.
n=0.582 moles
T=15+273.15=288.15ºK
R=0.082 atm.litres/ªKmol

V=(0.582 moles*0.082 atm l/ºKmol * 288.15ºK)/0.81 atm≈17.04 litres.

Sol: 17.04 litres.

It is a product