In the lab, frank has two solutions that contain alcohol and is mixing them with each other. he uses 100 milliliters less of solution a than solution b. solution a is 13% alcohol and solution b is 17% alcohol. how many milliliters of solution b does he use, if the resulting mixture has 347 milliliters of pure alcohol?

1200 ml

Explanation:

Let x be the quantity ( in ml ) of b solution,

∵  solution a is 100 milliliters less of than solution  b.

So, the quantity of solution a = 100 - x,

Now, solution a has 13% alcohol,

∴ Alcohol in solution a = 13% of (100-x) = = 0.13(x-100),

While solution b has 17% alcohol,

∴ Alcohol in solution b = 17% of x = 0.17x,

So, the quantity of alcohol in the mixture of a and b = 0.13(x-100) + 0.17x

= 0.13x - 13 + 0.17x

= 0.30x  - 13

According to the question,

Total quantity of alcohol in the mixture = 347 ml,

⇒ 0.30x  - 13 = 347

⇒ 0.30x = 347 + 13

⇒ 0.30x = 360

⇒ x = = 1200

Hence, the quantity of solution b is 1200 ml.

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong