Chloroform (chcl3), an important solvent, is produced by a reaction between methane and chlorine. ch4(g) + 3 cl2(g) chcl3(g) + 3 hcl(g) how many grams of ch4 is needed to produce 37.5 g chcl3?

CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g)
From the equation we notice that 1 mole of methane produces 1 mole of chloroform:
16 g Methane → 119.38 g Chloroform
?   g Methane → 37.5 g Chloroform
by cross multiplication:
= (16 * 37.5) / 119.38 = 5.0 g methane