How can 100ml of sodium hydroxide solution with a ph of 13.00 be converted to a sodium hydroxide solution with a ph of 12.00?

Chemical reaction: NaOH(aq) → Na⁺(aq) + OH⁻(aq).
V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0.1 L.
pOH = -log[OH⁻].
pH + pOH = 14.
pOH₁ = 14 - 13 = 1.
pOH₂ = 14 - 12 = 2.
[OH⁻]₁ = 10∧(-pOH₁) = 10⁻¹ M = 0.1 M.
[OH⁻]₂ = 10(-pOH₂) = 10⁻² M = 0.01 M.
[OH⁻]₁ · V₁(NaOH) = [OH⁻]₂ · V₂(NaOH).
0.1 M · 0.1 L = 0.01 M · V₂(NaOH).
V₂(NaOH) = 1 L, we can add 900 mL of water to convert solution of sodium hydroxide from pH=12 to pH=13, or we can add some strong acid.

Yes i think so not 100 percent sure though

The density of water is 1 g/cm cubed and in order for the pebble to sink its density has to be greater than the density of water and in order for the twig to float its density has to be less than the density of water