Calculate the ph of a solution that is 0.100 m hno2 and 1.00 m nano2

HNO₂ and NaNO₂ is considered as acidic buffer because HNO₂ is considered as weak acid and NaNO₂ is the conjugate base of this acid.

To find the original pH, we just use the Henderson-Hasselbach equation:
pH = pKa + log 

so pH = 3.4 + log  = 4.4

Hello!

For solving this question, you need to know the value of the pKa of HNO₂ before applying the Henderson-Hasselbach's equation. The pKa of HNO₂ can be found in tables or online and is 3,15. Now you can apply the equation in the following way:



So, the pH of this solution of HNO₂ and NaNO₂ should be 4,15

Have a nice day!

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic