A1.5 v battery moves 9000 c of charge around a circuit. part a by how much does the chemical energy of the battery decrease

In moving a charge through potential difference, work done can be calculated as follows:

Here, q is charge and V is potential difference.

(a) According to law of conservation of energy, chemical energy of the battery will be equal to work done, thus,

Putting the values,

Since, 1J=CV

Thus, the amount of chemical energy decreases will be 13500 J.

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."