For the oxidation of glucose (c6h12o6 + 6o2 --> 6h20 + 6co2), how many grams of oxygen gas will be consumed when 950g of glucose is oxidized completely?

You need to find the mole of glucose by using the formula n = m/Mr. Once you have found the mole you need to follow the stoichiometric process by unknown/known using the co-efficients. Then you need to multiple your answer by the known mole of glucose whoch you have previously calculated. After that you should get the mole of oxygen then you just need to transpose the equation to get m = n×Mr, substitute ypur answers in, remebering you can find your Mr via the period table, you have your answer

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