What is the mass of 2.23 x 10 to the 23rd atoms of sulfur?

The atomic mass of sulfur is 32.07 g/mole. 
From the Avagadro constant  1 mole of a substance contains 6.022 × 10^23 particles;
1 mole of sulfur contains 6.022 ×10^23 atoms
But 1 mole is equal to 32.07 g
Therefore; 
      6.022 ×10^23 atoms = 32.07
Thus; 2.23 × 10^23 atoms = ?
       = (2.23 ×10^23 ×32.07)/ 6.022×10^23
       = 11.876 g

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.