Ahydrogen atom orbital has n=5 and ml=−2 .what are the possible values of l for this orbital?

Answer : There are three possible values of 'l' which are 2, 3 and 4.

Solution : Given,

n = 5

There are 4 quantum numbers :

        values are 1, 2, 3, 4, .........

        values are 0 to (n-1)

        values are +l to -l

        values are to

when n = 5 then the value of l are,

l = 0, 1, 2, 3, 4

At l = 0,  

At l = 1,  

At l = 2,  

At l = 3,  

At l = 4,  

So, when then the possible values of l are,

l = 2, 3, 4

answer: your mm

explanation:

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3