When one mole of sodium chloride dissociates in water, it produces: 1 mole of ions ½ mole of sodium ions 2 moles of ions ½ mole of chloride ions none of these

Dissociation of NaCl in water is given as below,

                             NaCl ₍s₎    →    Na⁺ ₍aq₎  +  Cl⁻ ₍aq₎

According to this balanced equation the moles on RHS and LHS are as,

Moles on LHS,
                           NaCl ₍s₎   =   1 Mole

Moles on RHS,
                          Na⁺ ₍aq₎   =   1 Mole

                           Cl⁻ ₍aq₎   =    1 Mole
Result:
           When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.

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