How many atoms of potassium are in 0.250 mol of potassium carbonate, k2co3?

The  number  of  potassium  atom  that  are  in  0.25  moles   potassium  carbonate  is  calculated  as  follows

by  use  of Avogadro  contant

1  mole=  6.02  x10^23   atoms

what  about  0.25 moles,   
by  close  multiplication

{0.250 moles  x 6.02  x10^23}  /  1 mole  =  1.505  x10^23  atoms

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