Asolution containing sodium fluoride is mixed with one containing calcium nitrate to form a solution that is 0.015m in naf and 0.010m i. ca(no3)2. calculate the reaction quotient (q) for the possible cross product caf2, and compare q to the solubility product constant of caf2 to determine if a percipitate will form.

According to the reaction equation:

CaF2(s) ⇄  Ca2+(aq)  +  2F-(aq)

So the Q expression will be = [Ca2+][F-]^2 

and we will neglect the [ CaF2] as it is solid 

so, by substitution:

when we have [Ca2+] = 0.01

and [F-] = 0.015

Q = 0.01 * (0.015)^2

   = 6.3 x 10^-2

by comparing Q value which is 6.3 x 10^-2 and Ksp value which is 1.8 x 10^-5

So, we can see that Q > Ksp 

-that means precipitation will form as ion concentration are greater than

equilibrium concentration So, the reaction will proceed in reverse to achieve 

equilibrium . and the solution will be then supersaturated. 

Are there any options?

Engineers have contribute to society in many ways like making the technology we use today or any type of power energy material