How many moles of nitrogen gas are there in 16.8 l of this gas at stp?

According to Avogadro's Law, same volume of any gas at standard temperature and pressure will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                  n = moles = ?
                  V = Volume = 16.8 L

Solution:
                As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain

                           = ( 1 mole × 16.8 L) ÷ 22.4 L
                    
                           = 0.75 moles

Result:
           16.8 L of Nitrogen gas will contain 0.75 moles at standard temperature and pressure.

The correct name for n3-ion should be azide.

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.