What is the temperature of a 1.59 l flask containing 0.175 mol of ne at a pressure of 1.09 atm?

We can use the ideal gas law equation;
PV = nRT
P - pressure, V - volume , R - universal gas constant, n - number of moles and T - temperature 
P - 1 atm - 101 325 Pa
   1.09 atm - 1.09 atm x 101 325 Pa/atm = 110 444 Pa
n - 0.175 mol 
V - 1.59 x 10⁻³ m³
substituting the values in the equation 
110 444 Pa x 1.59 x 10⁻³ m³ = 0.175 mol x 8.314 Jmol⁻¹K⁻¹ x T
T = 120.70 K

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