Avolume of 90.0 ml of aqueous potassium hydroxide (koh) was titrated against a standard solution of sulfuric acid (h2so4). what was the molarity of the koh solution if 25.7 ml of 1.50 m h2so4 was needed? the equation is 2koh(aq)+h2so4(aq)→k2so4(aq)+2h2o(l )

Answer : The molarity of the KOH solution is, 0.856 M

Explanation :

The balanced chemical reaction is,

Using dilution law,

where,

= acidity of an base = 1

= basicity of an acid = 2

= concentration of = ?

= concentration of = 1.50 M

= volume of = 90 ml

= volume of = 25.7 ml

Now put all the given values in the above law, we get the concentration of the .

Therefore, the molarity of the KOH solution is, 0.856 M

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation:

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.