Chemistry, 26.07.2019 15:30, CadenSkinner2003

A0.100 l solution of 0.300 m agno3 is combined with a 0.100 l solution of 1.00 m na3po4. calculate the concentration of ag and po43– at equilibrium after the precipitation of ag3po4 (ksp = 8.89 × 10–17).

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Moles of Ag+ = 0.1 L * 0.3 m = 0.03 Moles

moles of PO4-3 = 0.1 L * 1 = 0.1 moles

According to the reaction equation which can be written as:

3Ag + + PO4 3- ↔ Ag3PO4(s)
initial 0.03 0.1
change -3X -X -

Equ (0.03-3X) (0.1-X)

when Ksp = [Ag]^3 [PO43-]

= (0.03-3X)^3 ( 0.1-X)

∴8.89 x 10^-17 = (0.03 - 3X)^3 (0.1-X)

8.89 x 10^-17 = 27 * (X-0.1)^4

∴ X = 2.9 x 10^-6

∴[Ag+] = 0.03 - (3 * (2.9 X 10^-6))

= 0.02998 M

[PO43-] = 0.1 - X = 0.1 - (4.3 x 10^-5)

= 0.0999 M

answered: steloiryancy

The concentration of $\bold { Ag^+}$ is 0.02998 M while the concentration of $\bold { PO_4^3^-}$ is 0.0999 M.

The reaction,

$\rm \bold{3Ag ^+ + PO_4^3^- \leftrightarrow Ag_3PO_4(s)}$

At equilibrium,

Concentration of $\bold { Ag^+}$ will be (0.03-3X)

Concentration of $\bold { PO_4^3^-}$ will be ( 0.1-X)

The moles of $\bold { Ag^+}$ is 0.03 Moles

Moles of $\bold { PO_4^3^-}$ is 0.1 moles

Solubility product constant formula,

$\rm \bold{ Ksp = [ Ag^+]^3[ PO_4^3^- ]}$

Put the values in the formula,Solve it for X

$\bold{8.89 x 10^-^1^7 = (0.03 - 3X)^3 (0.1-X)}$

$\bold {X = 2.9\times 10^-^6}$

Put the value of the X, in Ksp formula, we get

$\rm \bold{ [ Ag^+] = 0.02998 M}\\\\\\rm \bold{ [PO_4^3^-] = 0.0999 M }$

Hence we can conclude that the concentration of $\bold { Ag^+}$ is 0.02998 M while the concentration of $\bold { PO_4^3^-}$ is 0.0999 M.

To know more about Ksp, refer to the link:

link

answered: Guest

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

answered: Guest

What’s the solution?

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A0.100 l solution of 0.300 m agno3 is combined with a 0.100 l solution of 1.00 m na3po4. calculate t...