How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significant figures?

Answer : The mass of sucrose are, 402 grams

Solution :

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

where,

M = molarity of solution = 0.758 M = 0.758 mole/L

w = mass of solute (sucrose) = ?

M = molar mass of solute (sucrose) = 342 g/mole

V = volume of solution in liter = 1.55 L

Now put all the given values in the above formula, we get the mass of sucrose.

Therefore, the mass of sucrose are, 402 grams

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