Chemistry, 27.07.2019 07:00, Inktown4life0
The ka value for acetic acid, ch3cooh(aq), is 1.8× 10–5 m. calculate the ph of a 2.00 m acetic acid solution.
Answers: 1
![Ka= \frac{[CH_3COO^{-}]*[H_3O^{+}] }{[CH_3COOH]}](/tpl/images/0137/8863/3adae.png)
![Ka= \frac{x*x}{[CH_3COOH]_i-x} \\ \\ x= \sqrt{[CH_3COOH]_i*Ka}= \sqrt{2M*1,8*10^{-5} } \\ \\ x=0,006M=[H_3O^{+} ]](/tpl/images/0137/8863/0e7da.png)
![pH=-log[H_3O^{+}] =-log (0,006M)=2,22](/tpl/images/0137/8863/86a06.png)
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The ka value for acetic acid, ch3cooh(aq), is 1.8× 10–5 m. calculate the ph of a 2.00 m acetic acid...
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