Calculate the heat produced by combustion per liter of methanol. methanol has a density of 0.791 g/ml.

The  heat  produced  by  combustion   per  liter  of  methanol  is  calculated  as follows
heat   released  =  moles  x heat  of  combustion  of  methanol  
heat   of  combustion  of  CH3OH = 715 kj/mol
calculate  moles   first

 that  is ,moles =mass/molar  mass

calculate  the  mass  =  density  x volume(1L=1000ml)
= 0.791  x1000=791  g
molar  mass  of CH3Oh  =  32g/mol

moles  is therefore=   791 g /  32g/mol  =  24.72moles

heat released is therefore=  24.72mole  x  715  Kj/mol =17673.91 KJ