How many grams of i2 are needed to react with 30.1 g of n2h4?

The mass of iodine gas needed to react is 477.14 g

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of = 30.1 g

Molar mass of = 32 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of and iodine gas follows:

By Stoichiometry of the reaction:

1 mole of reacts with 2 moles of iodine gas

So, 0.94 moles of will react with = of iodine gas

Now, calculating the mass of iodine gas by using equation 1, we get:

Molar mass of iodine gas = 253.80 g/mol

Moles of iodine gas = 1.88 moles

Putting values in equation 1, we get:

Hence, the mass of iodine gas needed to react is 477.14 g

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

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