What is the empirical formula of a compound containing 24.56% potassium, 34.81% manganese, and 40.50% oxygen?   kmnokmno2k0.63mn0.63o2.53kmno4k3mn o2

Answer : The empirical formula of a compound is,

Solution :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 24.56 g

Mass of Mn = 34.81 g

Mass of O = 40.50 g

Molar mass of K = 40 g/mole

Molar mass of Mn = 55 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of K =

Moles of Mn =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K =

For Mn =

For O =

The ratio of K : Mn : O = 1 : 1 : 4

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula =

Therefore, the empirical formula of a compound is,

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