If i start with 5 grams of c3h8 what is my theoretical yield of water

C3H8  (propane) undergoes   combustion  to   produce  water  and  carbon (IV)  oxide  according  to   equation   below
C3H8(g)  +  5 O2(g)  >  3 CO2(g)  +  4 H2O(l)

calculate  the  moles  of  C3H8  used
mole =  mass/molar  mass
molar  mass  of  C3H8  = ( 12x3  )+(  1  x  8)=44  g/mol
moles  of  C3H8=  5g/  44 g/mol=  0.114  moles
by  use    of  mole  ratio  between  C3H8  to H2O   which  is  1:4  therefore  the  mole  of  water=  0.114  x4=0.456  moles
mass  of  water  =moles  of  water  x molar  mass  of  water

that  is  0.456 moles  x  18g/mol  = 8.208  grams

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.

The answer is 1.82 j/g°c