Chemistry, 29.07.2019 02:00, miyahvictoria

How much terephthalic acid could be made from 154 grams of para-xylene in moles? in grams?

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Hello!

1) In moles

The chemical reaction between para-xylene and oxygen to produce terephthalic acid and water is the following one:

C₆H₄(CH₃)₂ + 3O₂ → C₆H₄(CO₂H)₂ + 2H₂O

To calculate how much terephthalic acid in moles could be made from 154 grams of para-xylene in moles, we need to apply the following conversion factor to go from grams of para-xylene to moles of terephthalic acid, using the molar mass and the reaction coefficients:

$154gC_6H_4(CH_3)_2* \frac{1 mol_{C_6H_4(CH_3)_2}}{106,16 g_{C_6H_4(CH_3)_2}}* \frac{1 mol _{C_6H_4(CO_2H)_2}}{1 mol_{C_6H_4(CH_3)_2}} \\ =1,4506moles_{C_6H_4(CO_2H)_2}$

So, 1,4506 moles of Terephthalic Acid can be produced from 154 grams of para-xylene.

2) In grams

The process is similar as above. The chemical reaction between para-xylene and oxygen to produce terephthalic acid and water is the following one:

C₆H₄(CH₃)₂ + 3O₂ → C₆H₄(CO₂H)₂ + 2H₂O

To calculate how much terephthalic acid in grams could be made from 154 grams of para-xylene in moles, we need to apply the following conversion factor (similar as above) to go from grams of para-xylene to grams of terephthalic acid, using the molar masses of both compounds and the reaction coefficients:

$154gC_6H_4(CH_3)_2* \frac{1 mol_{C_6H_4(CH_3)_2}}{106,16 g_{C_6H_4(CH_3)_2}}* \frac{1 mol _{C_6H_4(CO_2H)_2}}{1 mol_{C_6H_4(CH_3)_2}}* \frac{166,13 g}{1 mol _{C_6H_4(CO_2H)_2}} \\ =240,995g_{C_6H_4(CO_2H)_2}$

The process is almost the same as above, just adding the calculation of the grams of terephthalic acids from the moles.

So, 240,995 grams of Terephthalic Acid can be produced from 154 grams of para-xylene.

Have a nice day!

answered: Guest

the grams of barium that are in 2.3 x 10^23 atoms of barium is 52.4 g (answer c)

calculation

mass = moles of ba x molar mass of ba

molar mass of ba from periodic table= 137.3 g/mol

use the avogadro's law constant to calculate the moles of barium

that is 1 mole = 6.02 x 10^23 atoms

? moles = 2.3 x 10^23 atoms

by cross multiplication

=(1 mole x 2.3x 10^23 atoms) / 6.02 x10^23 atoms)= 0.382 moles

mass is therefore = 137.3 g/mol x 0.382 mol = 52.4 ( answer c)

explanation: