The reaction 2a → a2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if the initial concentration of a was 4.00 m, what was the concentration of a (in m) after 180.0 min?

The integrated rate law for a second-order reaction is given by:

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

k = the rate constant for the reaction

Given: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min

Hence,

                                        = 4.858

Therefore, [A]t= 0.2058 M.

Concentration of A, after 180 min, is 0.2058 M

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sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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