1. aqueous solutions of chromium(iii) iodide and sodium hydroxide react to give a chromium(iii) hydroxide precipitate and aqueous sodium iodide. 2. aqueous solutions of iron(ii) sulfate and barium nitrate react to give a barium sulfate precipitate and aqueous iron(ii) nitrate. express your answer as a chemical equation. identify all of the phases in your answer. enter noreaction if there is no reaction.

1- The original equation of the reaction is :
CrI3 + NaOH → Cr(OH)3 + NaI 
but this is not a balanced equation so we have to balance it :
-first, we have 3 I atoms on the left side and 1  I atom on the right side 
so to makes the no.of atoms on both sides equal we put 3NaI instead of NaI
CrI3 + NaOH → Cr(OH)3 + 3NaI
- then no.of Na atoms on the left side is 1 and on the right side is 3 so, we put 3NaOH instead of NaOH
CrI3 + 3NaOH → Cr(OH)3 + 3NaI
now we have :
Cr atoms = 1 on both sides
I atoms = 3 on both sides
Na atoms = 3 on both sides
O&H atoms = 3 on both sides
So the final balanced equation of our reaction is:
CrI3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaI(aq)

2 - the chemical equation of the second reaction is :
FeSO4 + Ba(NO3)2 → BaSO4 + Fe(NO3)2
let's see if it is the balanced equation or not?
we have:
no of Fe atom on both sides = 1
no of (SO4) atom on both sides are equal
 no of Ba atom on both sides = 1
no of (NO3) group on both sides= 2 
so this is our balanced equation, so the final equation for this reaction is:
FeSO4(aq) + Ba(NO3)2(aq) →BaSO4(s) + Fe(NO3)2(aq)