How many moles of baso4 are formed if 0.5 moles of na2 so4 react with 60 g of bacl2? na2 so4 + bacl2 → baso4 + 2nacl

the balanced equation for the reaction is as follows
Na₂SO₄ + BaCl₂ > 2NaCl + BaSO₄ 
stoichiometry of Na₂SO₄ to BaCl₂ is 1:1
first we need to find out which the limiting reactant is
limiting reactant is fully used up in the reaction.
                                                                           
number of Na2So4 moles - 0.5 mol number of BaCl2 moles - 60 g / 208 g/mol = 0.288 mol
since molar ratio is 1:1 equal number of moles of both reactants should react with each other
                                                                         
therefore BaCl2 is the limiting reactant and Na2SO4 is in excess. amount of product formed depends on number of limiting reactant present.
stoichiometry of BaCl₂ to BaSO₄ is 1:1.
                                                                           
therefore number of BaSO4 moles formed - 0.288 mol

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is