When 10.0 ml of the 0.50 m solution is diluted to 100 ml as shown, what is the new concentration? ,

In this problem, we are asked to find the new concentration.

So, we use the dilution equation;

M1V1 = M2V2

Where M1 = concentration in molarity (moles/Liters) of the concentrated solution,

V2 =volume of the concentrated solution,

M2 =concentration in molarity of the dilute solution, and

V2 = volume of the dilute solution.

Before substituting the formula, convert the given mL to L since the unit for molarity is (moles/Liter).

Use the conversion factor (1000 mL = 1 L), so:

10.0 mL = 0.01 L

100 mL= 0.1 L

Now, we substitute the given (in liters) to the formula.

(0.50 M) (0.01 L) = M2(0.1 L)

M2 = [(0.50 M) (0.01 L)] / 0.1 L

M2 = 0.05 M

8 carbon atoms forming single bonds with 18 hydrogen atoms; a triple bond exists between the third and fourth carbon atom from the right

explanation: