Consider the chemical equilibrium of the following reaction

ch3cooh mc015-1.jpg ch3coo– (aq) + h+(aq)

what will happen to the chemical equilibrium of the solution if ch3coona is added?

the equilibrium will shifts to the right.

the equilibrium will shifts to the left.

the equilibrium will be unaffected.

the equilibrium will be lost.,

               The Equilibrium will shift to the left.

Explanation:

                      The reaction at equilibrium is as follow,

                              CH₃COOH       ↔    CH3COO⁻ + H⁺

According to Le Chatelier's Principle," When a system (reaction) at equilibrium is subjected to any stress (like change in Concentration, Pressure, Temperature e.t.c) the system (reaction) tends to adjust itself in such a way so as to minimize the effect of that change".

Hence, in above reaction when Sodium Acetate (source of CH₃COO⁻) is added the equilibrium will shift in left side and will decrease the concentration of CH₃COO⁻ions.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

2b2t

explanation:

2b2t