The combustion of acetylene gas is represented by this equation: 2c2h2(g) + 5o2(g) → 4co2(g) + 2h2o(g) how many grams of co2 and grams of h2o are produced when 52.0 g c2h2 burn in oxygen?

2C2H2 (g) +  5O2 (g) >  4CO2(g)  +  2H20 (g)

Calculate  the  moles of C2H2  used
that  52g/  26  g/mol(molar   mass of  C2H2)=   2moles

by   of  use  of reacting  ratio  between  C2H2  to  CO2  which  is  2  :4  therefore  the  moles  of  CO2  = 2  x4/2  =   4 moles
mass  of  CO2 is therefore  =   4 mol   x    44 g/ mol(molar  mass  of  CO2) =  176  grams

the  mole  of   water  is  calculated  by   use    mole  ratio  between  C2H2  to  H20  which  is  2:2  therefore  also =  2 moles
mass  of  water  is =    2  moles  x   18  g/mol  =  36grams