Consider the chemical equation in equilibrium. ch4(g) + h2o(g) mc029-1.jpg co(g) + 3h2(g) what will happen to the equilibrium of this reaction if the pressure is increased? the equilibrium will shift to the left to favor the reverse reaction. the equilibrium will shift to the right to favor the forward reaction. the equilibrium will not be affected by changing the pressure. the equilibrium will not be reestablished after this kind of stress.

The equilibrium will shift to the left to favor the reverse reaction.

Explanation:

This is a direct application of Le Chatelier's principle.

Le Chatelier's principle predicts that if a chage is introduced in a system in equilibrium, the system will react to compensate the change.

The increase in the concentration of CO, which is in the right side of the chemical equation,  takes the system out of the equilibrium.

Chemically, the greater number of molecules of CO means that more CO will react to favor the reverse reaction and restore the equilibrium with the increase of molecules in the left side (CH4 and H2O).

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer