1. for the balanced equation shown below, how many moles of o2 will react with 0.3020 moles of co2? 2c2h5oh + 6o2 → 4co2 + 6h2oa. 0.151 moles o2 b. 0.201 moles o2 c. 0.302 moles o2 d. 0.453 moles o2 2. how much heat is required to convert 74 grams of ice at -4 c into 74 grams of water at 52 c? use the information below: hf= 334 j/ga. 606 j b. 24,716 j c. 4000 j d. 41, 406 j

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

2b2t

explanation:

2b2t