What volume of 6.00 m naoh would be required to increase the ph to 4.93?

The Volume of  NaOH is mathematically given as

V=3.2 L

Volume of  NaOH

Generally the formula for PH is

Ph= Pka + log[A^-]/[HA]

4.93 = 4.76 + log((40+X)/(60-X))

0.17 = log ((40+X)/(60-X))

Therefore

X= 19.66 mmol = 0.019 mol

Generally the formula for molarity is

M= number of moles / volume    

6 = 0.019 / V

V=3.2 L

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According to this formula:
PH= Pka + ㏒[A^-]/[HA]
when we have the value of PH=4.93 & Pka (missing in your question) = 4.76 &
no.of mole of acetate = 40 mmol & no.of mole of acetic acid= 60
so by substitution:
4.93 = 4.76 + ㏒((40+X)/(60-X))
0.17 = ㏒ ((40+X)/(60-X))
∴X= 19.66 mmol = 0.019 mol
finally we can get the volume from this formula of the molarity:
molarity = number of moles / volume 
      6      = 0.019 / V
∴V= 0.0032 mL = 3.2 L

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic 

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