The oxygen gas produced in part a has a density of 1.43g/l. calculate the volume of of the o2 gas produced pg 76

The following is missing from the task above:

LiClO4(s) →LiCl(s) + 2O2(g)

m(LiClO4)=100g

a) m(O2)=?

From the reaction we got the following number of moles ratio:

n(LiClO4) : n(02) = 1 : 2

So, from the ratio, we can determine number of moles from O2:

n(02)= n(LiClO4) x 2 = (m/M) x 2 = 100/106.4 x 2= 1.9 mole

Now we can calculate the mass of oxygen:

m(O2)=n x M = 1.9 x 32 = 60.15 g

b) V(O2)=?

Now when we have the value of the mass of oxygen, we can calculate its volume with density equation:

d(O2)=m(O2)/V(O2)  ⇒  V(O2)= m(O2)/d(O2) 

V(O2) = 60.15 / 1.43 

V(02)  = 42.06 L

answer: mole of the gas

answer: mole of the gasexplanation:

answer: mole of the gasexplanation: this is because 1 mole of a gas is 22.4dm³, which is use in ideal gas