A15.0 kg chunk of ice falls off the top of an iceberg if the chunk of ice falls 8.00 to the surface of the water what is the kinetic energy of the chunk of ice when it hits the water and what is its velocity how do you work that out

When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE =  M g H
we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE
1/2 MV^2 = M g H
1/2 V^2 = g H
when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).
∴ v^2 = 2 * 9.8 * 8 = 156.8
∴ v= √156.8 = 12.5 m/s

Idk the answer sorry