How many grams of ammonia would be formed from the complete reaction of 4.50 moles hydrogen

51 grams of ammonia would be formed.

Explanation:

Moles of hydrogen gas = 4.50 moles

According to reaction, 3 moles of hydrogen gas gives 2 moles of ammonia gas.

Then 4.50 moles of hydrogen gas will give:

of ammonia

Mass of 3.00 moles of ammonia:

51 grams of ammonia would be formed.

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.