What is the empirical formula of a compound composed of 32.3 g potassium (k) and 6.61 g oxygen (o)?

Let's find the empirical formula step wise.

1st step - Get the mass of each element of the compound.

Here, the masses of K and O are given in grams.

Mass of K = 32.3 g

Mass of O = 6.61 g

2nd step - Get the molar mass of each element .

Molar mass of K = 39.10 g/mol

Molar mass of O = 16.00 g/mol

3rd step - find the moles of each element.

We know that,

moles (mol) = mass (g) / molar mass(g/mol)

Let's apply that formula to find the moles.

Moles of K = 32.3 g / 39.10 g/mol = 0.83 mol

Moles of O = 6.61 g / 16.00 g/mol = 0.41 mol

4th step - find the lowest number of moles

According to the above calculations, O has the lowest number of moles as 0.41 mol.

5th step - Divide the moles of each element by lowest number of moles to get the mole ratio between elements.

K = 0.83 mol / 0.41 mol = 2.02 = 2

O = 0.41 mol / 0.41 mol = 1

6th step - write the formula by using mole ratios.

Empirical formula = K₂O₁ = K₂O

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.