How many grams of naoh (mw = 40 g/mol) are present in 200 ml of 0.25 m naoh solution?

The correct answer is weight.

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: i hope this . =)

Ibelieve it's temperature! i'm not 100% sure.