Nitric acid and zinc react to form zinc nitrate, ammonium nitrate, and water. how many atoms of zinc react with 1.49g hno3? calculate the number of grams of zinc that must react with an excess of hno3 to form 29.1g nh4 no3.

For 1: The number of atoms of zinc are atoms.

For 2: Mass of zinc reacted are 95.1279 grams.

Explanation:

For the given chemical reaction, the equation follows:

To calculate the number of moles, we use the equation:

    ....(1)

For nitric acid:

Mass of nitric acid = 1.49 grams.

Molar mass of nitric acid = 63 g/mol

Putting values in equation 1, we get:

By Stoichiometry of the reaction:

10 moles of nitric acid reacts with 4 moles of zinc metal.

So 0.0236 moles of nitric acid will react with = of zinc metal

Now, according to Mole concept:

1 mole of an element contains number of atoms.

So, 0.00944 moles of zinc will contain number of atoms.

Hence, the number of atoms of zinc are atoms.

For ammonium nitrate:

Given mass of ammonium nitrate = 29.1 grams

Molar mass of ammonium nitrate = 80 g/mol

Putting values in equation 1, we get:

By Stoichiometry of the given reaction:

1 mole of ammonium nitrate is produced from 4 moles of zinc.

So, 0.36375 moles of ammonium nitrate will be produced from = of zinc.

Now, calculating the mass of zinc.

Moles of zinc = 1.455 moles

Molar mass of zinc = 65.38g/mol

Putting values in equation 1, we get:

Hence, mass of zinc reacted are 95.1279 grams.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j