In a mixture of he, ne, and xe gases with a total pressure of 925 atm, if there is 10.5 g of each gas in the mixture, what is the partial pressure of xe?

Partial pressure of Xe = 22.9 atm

Explanation:

Given:

Total pressure of gas mixture = 925 atm

Mass of He = Ne = Xe = 10.5 g

To determine:

Partial pressure of Xe

Explanation:

As per Dalton's Law in a mixture of gases the total pressure is the equal to the sum of partial pressures

In this case:

-------------(1)

Partial pressure of each gas can be expressed as:

-----(2)

where n(Xe) = moles of Xe

n(Total) = total moles

Therefore,

n(Total) = 0.080+2.625+0.525 = 3.23

Substituting for nXe, n(Total) and P(total) in equation (2)

the answer is symmetrical : )