Astrontium hydroxide solution is prepared by dissolving 21.78 g of strontium hydroxide in water to make 75.00 ml of solution. what is the molarity of this solution? next the strontium hydroxide solution prepared in part a is used to react with a 0.250 m nitric acid solution. write a balanced chemical equation to represent the reaction between the strontium hydroxide and nitric acid solutions. how many milliliters of the nitric acid solution from part b (0.250 m) is needed to completely react 34.21 ml of the strontium hydroxide solution from part a?

Molarity Sr (OH)₂ : 2,387  M

Milliliters of  HNO₃ : 653.27 ml

Further explanation

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products

Part A

dissolving 21.78 g of strontium hydroxide in water to make 75.00 mL of solution, the molarity:

Molar mass of Sr (OH)₂ is 121.6347 g / mol e

mole Sr (OH)₂ = 21.78 g: 121.6347 = 0.179

M = 0.179 mole: 0.075 Liter = 2,387

Part B

A balanced chemical equation

Sr (OH) ₂ + 2HNO₃ → Sr (NO₃) ₂ + 2H₂O

mole of 34.21 mL of Sr (OH) ₂ =

mole = 34.21 ml x 2,387 M

mole Sr (OH) ₂= 81,659 mlmole

from the chemical equation above Sr(OH)₂ mole : 2HNO₃ = 1: 2

so the mole needed by HNO₃ to react perfectly with Sr (OH) ₂ = 2 x 81,659 = 163,319 mlmole

So the amount of HNO₃ volume :

volume: 163,319 mmole x 0.25 M

volume = 653.27 ml

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Keywords: mole, strontium hydroxide solution,  a balanced chemical equation

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.