Asolution was prepared by dissolving 150.0 g of kcl in 295 g of water. calculate the mole fraction of kcl. (the formula weight of kcl is 74.6 g/mol. the formula weight of water is 18.0 g/mol.) express the mole fraction of kcl to two decimal places.

Calculate  the  mole  of  KCl  and  water  
moles  of  KCl=  150g/74.6g/mol=  2.01 moles
moles  of  water= 295g/18g/mol=16.39 moles
  calculate  the  total  number  of  moles
  2.01 +16.39 =18.4  moles
moles  fraction  of   KCl  is  therefore=2.01/18.4=  0.11mole

☆ionisation energy increases across a period from na -> ar☆ionisation energy decreases down a group from li -> fr☆ionic radius decreases across a period from na -> cl☆ionic radius increases down a groupfrom f -> ii hope it clarifies your doubts

Putting salt in vinegar water