In the lewis structure of the iodate ion, io3–, that satisfies the octet rule, the formal charge on the central iodine atom is

Answer :  The formal charge on the central iodine atom is, Zero (0).

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is,

As we know that iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in = 7 + 3(6) + 1 = 26

According to Lewis-dot structure, there are 10 number of bonding electrons and 16 number of non-bonding electrons.

Now we have to determine the formal charge on the central iodine atom.

Formula for formal charge :

Hence, the Lewis-dot structure of is shown below.

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

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