Calculate how much 95% ethyl alcohol will be required to dissolve 0.75 g of sulfanilamide at 78°c

The amount of 95% ethyl alcohol required to dissolve in 750 mg of sulfanilamide at 78°c is 3.57 mL

Sulfanilamide solubility in 95% ethyl alcohol (ethanol) is known to be 210 mg/ml.

Given that:

= 0.75 × 1000 mg

= 750 mg

Thus;

If 1 mL ethyl alcohol dissolves in 210 mg/ml

In 95% ethyl alcohol, the solubility of sulfanilamide concentration in mass 750 mg can be computed as follows:

1 mL = 210 mg/mL

x mL = 750 mg

∴

x = 3.57 mL

Therefore, we can conclude that the amount of 95% ethyl alcohol required to dissolve in 750 mg of sulfanilamide at 78°c is 3.57 mL

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