Chemistry, 04.08.2019 13:20, RKennedy3448

The following equation is one way to prepare oxygen in a lab.2kclo3 → 2kcl + 3o2molar mass info: mm o2 = 32 g/mol mm kcl = 74.55 g/mol mm kclo3 = 122.55 g/molif 25.6 g of kcl are produced, then how many moles of kclo3 were consumed? a. 0.209 molb. 0.687 molc. 0.343 mold. 0.172 mol

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The following equation is one way to prepare oxygen in a lab.2kclo3 → 2kcl + 3o2molar mass info: mm...