Describe, in detail, how to make 2.0 liters of a 1.0 molar hcl solution from a 12.5 molar hcl stock solution.

We are starting with a 12.5 M HCl solution. We want 2.0 L of a 1.0 M HCl solution.

We can start with the solution we want to make and work backwards to determine how much of the 12.5 M solution is required.

2.0L x 1.0 mol/L = 2.0 moles HCl

To make 2 L of a 1.0M solution of HCl, we need 2.0 moles of HCl that we get from the stock solution.

2.0 moles HCl / 12.5 mol/L = 0.16 L = 160 mL of solution.

Therefore, we need 160 mL of the 12.5 M solution of HCl to make 2 L of a 1.0M HCl solution.

The answer is 323 g.

So3 that’s what i think