In the following reaction, how many grams of nabr will produce 244 grams of nano3? pb(no3)2(aq) 2 nabr(aq) pbbr2(s) 2 nano3(aq) the molar mass of nabr is 102.9 grams and that of nano3 is 85 grams

Answer : The mass of is, 295.323 grams

Solution :

First we have to calculate the moles of .

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 2 moles of

So, 2.87 moles of react with 2.87 moles of

Now we have to calculate the mass of NaBr.

Therefore, the mass mass of is, 295.323 grams

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

the dependant variable is spilled water

the independent is the heat